Velocity : v(t) = d_x(t)/dt = 2At +B Acceleration : a(t) = d_v(t)/dt = 2A Experi
ID: 1530555 • Letter: V
Question
Velocity : v(t) = d_x(t)/dt = 2At +B Acceleration : a(t) = d_v(t)/dt = 2A Experiments acceleration : a_exp = 2A Newton's second law : F = ma For a frictionless ramp, the force responsible for the constant acceleration is the component of the weight parallel to the ramp. Mg sin(theta) = ma a = g sin(theta) where g is acceleration due to gravity. The angle of inclination theta can be determined from the Length (L) and height (h) of the ramp. Sin(theta) = h/L Experimentally the acceleration down the ramp can be calculated as a_exp = g(n)/L = 2A The acceleration due to gravity can then be determined by g_exp = a_exp L/h = 2A L/h Assume the track has a length L = 1.0 m, and we release a cart of known mass from five different heights.Explanation / Answer
Given
a exp = 2*A
and g exp = 2A(L/h), L= 0.1 m,
h (m) A (m/s2) a exp (m/s2) g exp (m/s2)
0.02 0.089 0.179 2(0.179)(0.1/0.02) = 1.79
0.04 0.2 0.4 2(0.2)(0.1/0.04) = 1
0.06 0.3 0.6 2(0.3)(0.1/0.06) = 1
0.08 0.38 0.76 2(0.38)(0.1/0.08) = 0.95
0.1 0.46 0.92 2(0.46)(0.1/0.1) =0.92
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.