Two small plastic spheres are given positive electrical charges When they are a

Question

Two small plastic spheres are given positive electrical charges When they are a distance of 14.4 cm apart, the repulsive force between them has a magnitude of 0.220 N For related problem solving tips and strategies, you may want to view a Video Tutor Solution of Force between two point charges. What is the charge on each sphere if the two charges are equal? What is the charge on first sphere if it has four times the charge of the second sphere? What is the charge on the second sphere described in the previous part?

Explanation / Answer

F = kq1*q2/r^2

r = 14.4 cm = 0.144 m

q1 = q2 = q

F = 0.220 N

k = 9 x 10^9

F = kq^2/r^2

q = sqrt(F*r^2/k)

q = 7.12 x 10^-7 C

part b )

q2 = 4q1

F = k*q1*4q1/r^2

q1 = sqrt(F*r^2/k*4)

q1 = 3.56 x 10^-7 C

part c )

q2 = 4q1

q2 = 1.42 x 10^-6 C

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.