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webassign.net Graduate School Wayn... Prerequisites l UDM Col Trust Me, I'm a PA cnzabelaoakl Phy 101 W17 Chapter 6 EXAMPLE 6.2 How Good Are the Bumpers? Goal Find an impulse and estimate a force in a collision of a moving object with a stationary object. Problem In a crash test, a car of mass 1.50 x 10 kg collides with a wall and rebounds as in the 2.60 m/ figure. The initial and final velocities of the car are va 15.0 m/s and vy 2.60 m/s, respectively. If the collision lasts for 0.150 s find (a) the impulse delivered to the car due to the collision and (b) the size and direction of the average force exerted on the car. Strategy This problem is similar to the previous example, except that the initial and final momenta are both nonzero. Find the momenta and substitute into the im entum theoret m, solving for pulse-mom SOLUTION (a) Find the impulse delivered to the car. Calculate the in al and final momenta my, 1.50 x 103 15.0 m/s 2.25 x 104 kg of the car. m/s pr my 1.50 x 103 kg)(+2.600 m/s) 3.90 x 10 kg m/s The impulse is just the difference py pr- +3.90 x 103 kg m/s 2.25 x 10 kg between the final and initial momenta m/s 1 2.64 x 104 kg m/s (b) Find the average force exerted on the car. Ap 2.64 x 104 kg m/s Apply the impulse-momentum -1.76 x 105 N theorem 0.150 s LEARN MORE Remarks When the car doesn't rebound off the wall, the average force exerted on the car is smaller than the value just calculated. With a final momentum of zero, the car undergoes a smaller change in Chegg Study I Guided S Google Search Joan Geller FactsExplanation / Answer
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the correct options are,
1st option
3rd option
practice it.
Impulse = change in momentum
= m*(vf - vi)
= 1.51*10^3*(2.18 - (-15.7))
= 2.70*10^4 N
Excercise
we know, Impulse = Favg*delta_t
==> Favg = Impulse/delta_t
= 2.70*10^4/0.168
= 1.61*10^5 N
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