I am having a little trouble finding the direction of this force, Ive tried tan-

Question

I am having a little trouble finding the direction of this force, Ive tried tan-1 and cannot figure it out

9. 3/6 points Previous Answers SerCP9 15.P.011.MI,FB My Notes Ask Your Teach Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q 4.80 nC at the origin. (Let r12 0.250 m.) magnitude 1.36E-5 N direction agram and determine which quadrant contains the angle of the net force counterclockwise from the +x-axis Enter a number. 6.00 nC 0.100 m 3.00 nC

Explanation / Answer

Given that

charge q1=6 nC

charge q=4.8 nc

charge q2=-3 nC

step;2

now we find the net force of attraction b/w charge q

the force F1=9*10^9*4.8*6*10^-18/0.25^2=4147.2*10^-9 N

the force F2=9*10^9*4.8*-3*10^-18/0.1^2=-12960*10^-9 N

the magnitude Fnet=[12960^2+4147.2^2]^1/2=13607.4 nN

direction=tan^-1[12960/4147.2]=107.7 degree

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