A diatomic gas begins with a pressure of 1.00 atm and a volume of 2.00 m^3. It t

Question

A diatomic gas begins with a pressure of 1.00 atm and a volume of 2.00 m^3. It then expands until its pressure is 2.50 atm and its volume is 3.50 m^3. On a P-V diagram, this process is a straight line. Find the work done by the gas, and the heat absorbed during the process. A cylinder contains 0.350 mol of a polyatomic ideal gas. Initially its volume is 7.00 x 10^3 m^3 and its temperature is 300 K. The gas first expands at constant pressure until its volume doubles. Then it expands adiabatically until the temperature returns to its initial value, (a) What is the final volume? (b) What is the total heat absorbed during this process? (c) What is the total work done by the gas during this process?

Explanation / Answer

3) Area under the curve is 1/2 * (change in Preasure)*(change in volume)
   = 1/2*1.5*1.5 = 1.5 atm.m3 = 0.153*106 J

4) n= 0.35 moles, Vi = 7*10-3 m3 , Vf= 2*7*10-3 = 14*10-3 m3

During Adiabatic process, no heat is gained or lost by the system

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