A rigid sphere has a valve that can be opened or closed. The sphere with the val

Question

A rigid sphere has a valve that can be opened or closed. The sphere with the valve open is placed in boiling water in a room where the air pressure is 1.0 atm. After a long period of time has elapsed, the valve is closed. What will be the pressure inside the sphere if it is then placed in a mixture of ice and water? Express your answer to two significant figures and include the appropriate units. What will be the pressure inside the sphere if it is then placed in an insulated box filled with dry ice? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Given

   the pressure inside the boiling water in a room is P1 = 1 atm

   we know that the temperature of boiling water is 100 0C = 373.15 k

from ideal gas equation pv = nRT
   her the volume and no of moles are constant so

given that the tmeperature T2 = 0 0C = 273.15 k
   P2/P1 = T2/T1

   P2 = T2*p1/T1 = 273.15*1/373.15 atm = 0.7320 atm

PArt B

now at dry ice teperature is T2 = -78.5 0C = 194.65 k

pressure

           P2 = T2*p1/T1 = 194.65*1/373.15 atm = 0.521640 atm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.