Two positive point charges, each of magnitude q , are fixed on the y -axis at th
ID: 1527609 • Letter: T
Question
Two positive point charges, each of magnitude q, are fixed on the y-axis at the points y=+a and y=a. Take the potential to be zero at an infinite distance from the charges.
Part A
What is the potential V0 at the origin?
Express your answer in terms of the given quantities and appropriate constants.
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Part B
Find the potential at the point (x,0).
Express your answer in terms of the given quantities and appropriate constants.
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Part C
What is the potential when xa?
Express your answer in terms of the given quantities and appropriate constants.
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Part D
Explain why this result is obtained.
Two positive point charges, each of magnitude q, are fixed on the y-axis at the points y=+a and y=a. Take the potential to be zero at an infinite distance from the charges.
Part A
What is the potential V0 at the origin?
Express your answer in terms of the given quantities and appropriate constants.
V0 =SubmitMy AnswersGive Up
Part B
Find the potential at the point (x,0).
Express your answer in terms of the given quantities and appropriate constants.
V(x) =SubmitMy AnswersGive Up
Part C
What is the potential when xa?
Express your answer in terms of the given quantities and appropriate constants.
V(x) =SubmitMy AnswersGive Up
Part D
Explain why this result is obtained.
Explanation / Answer
PART A:
This is particularly easy, since both scalar electric potentials are the same (same q, same r = a, direction doesn’t matter). V0 = V0t + V0b = 2V0t = 2kq /a
PART B:
The x-axis is still symmetric (same distance to each charge), so V = 2Vt, and we can use the Pythagorean theorem for r. V = 2Vt = 2kq /r = (1 /40) (2q/ r)= (1/40) (2q / (a^2 + x^2)
PART C:
As x gets much bigger than a, (a^2 + x^2) x 2 , so V = 2kq /r^2 k.2q/x^2
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