It the previous discussion we found that both the electric fields of a single po

Question

It the previous discussion we found that both the electric fields of a single point charge is described by an inverse-square relationship: Field = C/r^2. What happens to the value of the field at distances very close to the charge (r very small) and at distances very far from the charge (r very large)? The electric field of a ring of charge is given by E = Cz/(z^2 + R^2)^3/2. What happens to the field at a) z = 0; b) z R? The electric field of a line of charge is given by E = C/r(r^2 + (1/2)^2)^1/2. What happens to the field at a) r = 0; b) r (L/2)? The electric field of a disk of charge is given by E = C[1 - z/(z^2 + R^2)^1/2]. What happens to the field at a) z = 0; b) z R?

Explanation / Answer

1.

Electric field is inversly proportional to the square of the distances as given in the problem

field =C/r2

when r is very small ,electric field becomes very large and when r is very large electric field becomes very less.

2.

a)

for z=0

E=0

b)

when Z<<R

E=0 (approximately)

c)

when Z>>R

E=CZ/Z3=C/Z2

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