Development of Learning outcomes for Engineering Calculus Redesign of Engineerin
ID: 1527390 • Letter: D
Question
Development of Learning outcomes for Engineering Calculus Redesign of Engineering Calculus I and II recitation Development of JIT curriculum for PPP and LEEP students to succeed in Engineering Calculus Workshop coordinator for iLearn A parallel-plate capacitor is made from two aluminum-foil sheets, each 4.3 cm wide and 5.1 m long. Between the sheets is a Teflon strip of the same width and length that is 0.025 mm thick, (this is d). What is the capacitance of this capacitor? (The dielectric constant of Teflon is K = 2.1) If the voltage across this capacitor is 250.0V what is the charge on each plate and how much energy is stored in the capacitor?Explanation / Answer
C = k *o*A/d
C = 2.1*8.85*10^-12*5.1*0.043/0.025*10^-3
C = 0.163*10^-6 F
q = cv = 40.76*10^-6 C
u = 1/2cv^2 = 5.1*10^-3 J
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