1) Two parallel conducting plates are separated by a distance d = 12.0 cm. Plate
ID: 1527108 • Letter: 1
Question
1) Two parallel conducting plates are separated by a distance d = 12.0 cm. Plate B, which is at a higher potential has a value of 620 V. The potential at x = 7.50 cm from the plate B is 84.9 V. See diagram below. (a) What is the potential of plate A? V (b) What is the direction of the electric field lines between the plates? toward the left toward the right upward downward
(a) What is the potential of plate A?
_V
(b) What is the direction of the electric field lines between the plates?
toward the left
toward the right
upward
downward
2). A large capacitance of 1.98 mF is needed for a certain application.
(a) Calculate the area the parallel plates of such a capacitor must have if they are separated by 4.80 µm of Teflon, which has a dielectric constant of 2.1.
(b) What is the maximum voltage that can be applied if the dielectric strength for Teflon is 60 106 V/m
(c) Find the maximum charge that can be stored.
(d) Calculate the volume of Teflon alone in the capacitor.
3)Find the total capacitance of the combination of capacitors shown in the figure below.
(C1 = 2.42 µF,
C2 = 19.2 µF.)
Explanation / Answer
as per the chegg rules, you should post one quenstion at once. so i am answering one answer only
3rd question Answer :
Here C1 = 2.42F and C2 = 19.2 F
We know the capacitors combination formulas as
Capacitors in Parallel combination : Ct = C1 + C2 + C3....
Capacitors in series combination: 1/Ct = 1/C1 + 1/C2 + 1/C3...
On the left side, C1 in series with 3.5 uF:
1/Ct1 = 1/(2.42) + 1/(3.5)
1/Ct1 = 0.4132+0.2857 =0.6989 F
Ct1 = 1.4308 uF
Right side we have C2 in parallel with 0.75 uF
Ct2 = 19.2 + 0.75 = 19.95 uF
Ct2 is in series with 1.5 uF
19.95 F in series with 1.5 F
Ct3 = 1.395 uF
We have the 8.0 uF in the middle which is in parallel with both Ct1 and Ct3 , So
1.4308 uF in parallel with 8.0 uF in parallel with 1.395 uF
Total combined capacitance, C = 1.4308 + 8.0 + 1.395 =10.826 F
C = 10.826 uF
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.