VA Assignment 3 C www.webassign ne 15467738 t/web/Student/Assignment-Responses/l

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VA Assignment 3 C www.webassign ne 15467738 t/web/Student/Assignment-Responses/last?dep 10,0 m Need Help? Read It 011 points. Previous Answers SerCP10 3.P.06 My Notes Ask Your Teacher By throwing a ball at an angle of 45 a girl can throw it a maximum horizontal distance of R on a level field. How far can she throw the same ball vertically upward? Assume her muscles give the ball the same speed in each case. Use any variable or symbol stated above as necessary.) Ay Need Help? Read It Submit Assignment save Assignment Progress Home My Assignments Extension Request WebAssign 4.0 ® 1807-2017 Advanced Instructio 048 PM 1/31/2017

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Lets call the initial velocity vi

The upward compnent of the velocity is

vi * sin(45) = 0.707*vi

The motion equation for the vertical movement is

H = 0.707vi - 0.5*9.8*t^2 where t is the flight time
we put H as zero , to calculte the total flight time until the ball hits the ground
0.707vi = 4.9 t^2
t = 0.144 * square-root(vi)

the horizontal movement is at contant speed of
vi*cos(45) = 0.707vi (assuming no air friction)
the movement is governed by the following equation

R = 0.707vi * t = 0.766vi * 0.144 * sqrt(vi)
vi = R^3/2/0.0326
Now, if she throw the ball at that speed directly upward,
the equation becoms

H = R^3/2/0.0326*t - 0.5*9.8*t^2
and the speed during flight
v = R^3/2/0.0326 - 9.8t
at the top of the trajectory v = 0 therefor t at that time is
t = R^3/2/0.319secs
put that value to the motion equation and you get
H = R^3/2/0.0326*(R^3/2/0.319)- 0.5*9.8*(R^3/(0.319)^2)

H = 48R^3meter

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