number 14 A ball, thrown downward from the top of a building with an initial spe
ID: 1526829 • Letter: N
Question
number 14
Explanation / Answer
u = 98 m/s
v = 0
a = 9.8 m/s^2
v^2 = u^2 - 2*a*s
0 = 98^2 - 2*9.8*s
s = 490 m
Maximum height reached by the stone, including the height of tower = 215.6 + 490 = 705.6 m
v = u - a*t
0 = 98 - 9.8 * t
t = 10 s
Time when it passes the top of the tower , = 2*t = 20 s
s = u*t + 1/2*a*t^2
705.6 = 0 + 1/2 * 9.8 * t^2
t = 12 s
Total travel time since launch, = 12 + 10 = 22 s
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