Problem 23.36 What are the strength and direction of the electric field at the p
ID: 1526749 • Letter: P
Question
Problem 23.36 What are the strength and direction of the electric field at the position indicated by the dot in figure(Figure Figure 1 of 1 10 nC 4.0 cm 2.0 cm 5.0 nC 10 nC Part A Give your answer in terms of the horizontal and vertical components. Take the positive directions to be up and to the right. Express your answer using two significant figures. Enter your answers numerically separated by a comma. Ez, Ey NAC Submit My Answers Give Up Part B Give your answer as a magnitude and angle measured from the positive x-axis Express your answer using two significant figures. N/C Submit My Answers Give UpExplanation / Answer
A)
let
q1 = 10 nc (top right)
q2 = 10 nc (lower left)
q3 = -5 nc
Ex = -(k*q1/0.04^2 + k*q2/(0.04^2 + 0.02^2)*4/sqrt(4^2 + 2^2) )
= -(9*10^9*10*10^-9/0.04^2 + 9*10^9*10*10^-9/(0.04^2 + 0.02^2)*(4/sqrt(4^2 + 2^2)) )
= -9.65*10^4 N/c
Ey = k*q3/0.02^2 + k*q2/(0.04^2 + 0.02^2)*4/sqrt(4^2 + 2^2) )
= -9*10^9*5*10^-9/0.02^2 + 9*10^9*10*10^-9/(0.04^2 + 0.02^2)*(2/sqrt(4^2 + 2^2))
= -9.24*10^4 N/c
B) E = sqrt(Ex^2 + Ey^2)
= sqrt(9.65^2 + 9.24^2)*10^4
= 1.34*10^5 N/c
C) theta = tan^-1(Ey/Ex)
= tan^-1(9.24/9.65)
= 43.7 degrees below -x axis
= 133.7 degrees with +x axis in closkwise direction.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.