ATTENTION: I tried to work this out and -1.481*10^-5 is not the correct answer.

Question

ATTENTION: I tried to work this out and -1.481*10^-5 is not the correct answer.

Forces in a Three-Charge System Coulomb's law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is FI -K where K 1 and eo 8.854 x 10-12 C2/(N. m is the permittivity of free space. Consider two point charges located on the x axis one charge, 1 0 n is located at r1 -1.670 m the second charge, 32.5 nC, is at the origin (z 0.0000 Part A What is the net force exerted by these two charges on a third charge q 47.0 nC placed between qu and 92 at ac3 1.140 m Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures. Force on Submit Hints My Answers Give Up Review Part

Explanation / Answer

here,

q1 = - 10 * 10^-9 C at x1 = - 1.67 m

q2 = 32.5 * 10^-9 C at x2 = 0 m

q3 = 47 * 10^-9 C at x3 = - 1.14 m

the net force exerted by these two charges on third , F = k * q1 * q3 /( x1 - x3)^2 + k * q2 * q3 /( x3^2)

F = 9 * 10^9 * 10^-9 * 10^-9 * ( 10 * 47 /( 1.67 - 1.14)^2 + 32.5 * 47 /( 1.14)^2)

F = 2.56 * 10^-5 N

the net force on q3 is 2.56 * 10^-5 N towards q1

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