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flipitphysics.com/Course/ViewProblem?unitltemID 2422604&enrollmentID; 238183 Monday, January 30 I 10:44 PM Fliplt Physics Physics 4B: EM and Heat, S2017 California State University, Fresno Unit 2 Homework: HW2 Of Ch17&20 Deadline: 100% until Monday, January 30 at 11:59 PM Tipler6 20,P028. 1) A copper collar is to fit tightly about a steel shaft whose diameter is 6.0035 cm at 22 C. The inside diameter of the copper collar at that temperature is 5.9800 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the temperature of both the steel shaft and copper collar are raised simultaneously? Submit 1039.6 You currently have 1 submissions for this question, Only 10 submission are allowed. You can make 9 more submissions for this question.Explanation / Answer
change in diameter to fit exactly is 6.0035-5.9800 = 0.0235 cm
change in area is A2-A1 = pi*r2^2 -pi*r1^2 = ((3.142*(0.060035/2)^2) - (3.142*(0.0589/2)^2))
A2-A1 = 1.06*10^-4 m^2
original area is pi*r1^2 = 3.142*(0.0598/2)^2 = 2.808*10^-3 m^2
using coefficient of areal expansion of cooper collar is 2*16.6*10^-6
Beta = (A2-A1)/(A1*dT)
2*16.6*10^-6 = (1.06*10^-4)/(2.808*10^-3*(T-22)) = 1159 C
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