Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

ships A and B leave port together. For the next two hours, ship A travels at 25.

ID: 1526329 • Letter: S

Question

ships A and B leave port together. For the next two hours, ship A travels at 25.0 mph in a direction 70.0 degree west of north while the ship B travels 55.0 degree east of north at 40.0 mph A: What is the distance between the two ships two hours after they depart? B: What is the speed of ship A as seen by ship B? ships A and B leave port together. For the next two hours, ship A travels at 25.0 mph in a direction 70.0 degree west of north while the ship B travels 55.0 degree east of north at 40.0 mph A: What is the distance between the two ships two hours after they depart? B: What is the speed of ship A as seen by ship B? ships A and B leave port together. For the next two hours, ship A travels at 25.0 mph in a direction 70.0 degree west of north while the ship B travels 55.0 degree east of north at 40.0 mph A: What is the distance between the two ships two hours after they depart? B: What is the speed of ship A as seen by ship B?

Explanation / Answer

here,

speed of ship A , vA = 25 mph * ( -sin(70) i + cos(70) j)

vA = ( - 23.49 i + 8.55 j) mph

speed of ship B , vB = 40 mph * ( sin(55) i + cos(55) j)

vB = (32.77 i + 22.9 j) mph

A)

vA - vB = ( - 56.26 i - 14.35 j ) mph

for 2 hours

xA - xB = ( vA - vB) * 2 = (- 112.52 - 28.7 j) mi

the distance between the two ships two hours after they depart , d = sqrt(112.5^2 + 28.7^2) = 116.1 mi

B)

the speed of ship A as seen from B , v = |vA - vB| = sqrt(56.26^2 + 14.35^2)

v = 58.06 mph