1. (a) Write down the equation for the capacitance of a parallel plate capacitor

Question

1. (a) Write down the equation for the capacitance of a parallel plate capacitor with dielectric material inside. Identify the meaning of each symbol in the equation. 12 CA (b) A parallel capacitor has plates with cm x 40.0 cm.The separation between plates is 0.2 If the capacitor filled with Mica with dielectric constant of7.00, calculate the capacitance. loo-o.ol All in 40.0cm o.4m meters 0,000m (c) f the plates were connected to 12.0 v battery, calculate the magnitude of the charge on a plate (d) calculate the total energy stored in the capacitor when connected to 12.0v battery. (e) you increase the voltage between the capacitor what would happen to the following quantities Reason: Capacitance Reason: Energy stored

Explanation / Answer

here,

a)

the capacitance of capacitor when a dielectric is inserted between the plates , C= k * area * e0 /d

area - area of each plate

d - sepration between plates

k - dielectric constant

b)

area = 1 * 40 cm^2 = 40 * 10^-4 m^2

d = 0.2 m

k = 7

C= k * area * e0 /d

C = 7 * 40 * 10^-4 * 8.85 * 10^-12 /0.2 = 1.24 * 10^-13 F

the capacitance of capacitor when a dielectric is inserted between the plates is 1.24 * 10^-12 F

c)

V = 12 V

the magnitude of charge , Q = C * V

Q = 1.49 * 10^-11 C

d)

total energy stored , E = 0.5 * C * V^2

E = 0.5 * 1.24 * 10^-12 * 12^2

E = 8.93 * 10^-11 J

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