Four tubes are set up in the lab at sea level as shown by the figure. The letter
ID: 1525112 • Letter: F
Question
Four tubes are set up in the lab at sea level as shown by the figure. The letter under each tube corresponds the question with the same letter.
1 atm = 101300 Pa = 101300 N/m2
water = 1000 kg/m3
1) What is the pressure pushing down on the surface of the water in tube (a) from the outside?
2.) Tube (b) is also filled with water, A1 is 0.05m2 and A2 is 0.08m2 Two pistons are placed in both ends of the tube and forces, F1 and F2 are exerted on the pistons so that they remain at the same height. If F1 = 20N what is F2?
3) Tube (c) is again filled with water. A1 and A2 are the same as in part (b). Two pistons apply different forces to the water in the tube so that the water in the right side of the tube is a height h = 0.43m above the height of the water in the left side of the tube. If F2 = 138 N what is F1?
4) Now two fluids are placed in the same tube (d). Both sides are open to the atmosphere without pistons. One fluid is water and the other (on top of the water in the left branch of the tube) is an oil of unknown density. l = 135mm and d = 12.3mm. What is the density of the oil?
------
Do not copy work from others. I would like all 4 to be answered.
(a) (b) (c) (d)Explanation / Answer
a) P = 1 atm = 1.013*10^5 pa
b) use Pascal's law
P2 = P1
F2/A2 = F1/A1
F2 = F1*(A2/A1)
= 20*(0.08/0.05)
= 32 N
c) P1 = P2 + rho*g*h
F1/A1 = F2/A2 + rho*g*h
F1 = F2*(A1/A2) + rho*g*h*A1
= 138*(0.05/0.08) + 1000*9.8*0.43*0.05
= 297 N
d) use, rho_oil*g*(d+l) = rho_water*g*l
rho_oil = rho_water*l/(d+l)
= 1000*135/(12.3 + 135)
= 916 kg/m^3
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.