O 1/30/2017 11:55 PM A 88.5/100 Gradebook Print Periodic Table Calculator Questi

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O 1/30/2017 11:55 PM A 88.5/100 Gradebook Print Periodic Table Calculator Question 6 of 13 ncorrect Map A 2a Sapling Learning macmillan learning Two identical guitar strings are prepared such that they have the same length (2.04 m) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the 3rd harmonic. The other string is plucked in a different location, primarily exciting the 5th harmonic. The resulting sounds give rise to a beat frequency of 324 Hz. What is the wave propagation speed on the guitar strings? Incorrect. For waves travelling through a Number medium with nodes (fixed points) at ends, the allowed frequencies are: 1321.92 nv 2L. A Previous Try Again Next Exit

Explanation / Answer

Given Length of Strings L=m=2.04m

Beat Frequencey is n=324 Hz

Now to calculate the frequency

The first string vibrate at 3 harmonic while second at 5th

therefore f1 ~ f2 =n

or  f1 ~ f2 = 324

or 2f= 324

f= 162 Hz

Now we knows that f = v / Lamda

lamda (wavelength) can be calculated as 2*L = 2 x2.04 = 4.08 m

putting in above formula in bold we get v =162*4.08 =660.96 m /s ANSWER

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