Review questions: A) A plate carries a charge of -4 C, while a rod carries a cha

Question

Review questions: A) A plate carries a charge of -4 C, while a rod carries a charge of 1.50 C. How many electrons must be transferred from the plate to the rod, so that both objects have the same charge? B)Two tiny conducting spheres are identical and carry charges of -17.3C and +63.1C. They are separated by a distance of 2.01 cm. (a) What is the magnitude of the force that each sphere experiences? (b) The spheres are brought into contact and then separated to a distance of 2.01 cm. Determine the magnitude of the force that each sphere now experiences. Review questions: A) A plate carries a charge of -4 C, while a rod carries a charge of 1.50 C. How many electrons must be transferred from the plate to the rod, so that both objects have the same charge? B)Two tiny conducting spheres are identical and carry charges of -17.3C and +63.1C. They are separated by a distance of 2.01 cm. (a) What is the magnitude of the force that each sphere experiences? (b) The spheres are brought into contact and then separated to a distance of 2.01 cm. Determine the magnitude of the force that each sphere now experiences. A) A plate carries a charge of -4 C, while a rod carries a charge of 1.50 C. How many electrons must be transferred from the plate to the rod, so that both objects have the same charge? B)Two tiny conducting spheres are identical and carry charges of -17.3C and +63.1C. They are separated by a distance of 2.01 cm. (a) What is the magnitude of the force that each sphere experiences? (b) The spheres are brought into contact and then separated to a distance of 2.01 cm. Determine the magnitude of the force that each sphere now experiences.

Explanation / Answer

here,

charge , q1 = - 4 uC

q2 = 1.5 uC

for the both objects to have same charge , q = (q1 + q2)/2

q = ( - 4 + 1.5) /2 uC

q = - 2.75 uC

the charge transferred from plate to rod , q' = q1 - q

q' = - 1.25 uC = -1.25 * 10^-6 C

the number of electrons transferred , n = q'/e

n = - 1.25 * 10^-6 /( - 1.6 * 10^-19) = 7.81 * 10^12 electrons

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