The following data pertain to the following experiment for measuring the volume

Question

The following data pertain to the following experiment for measuring the volume of air insider a core sample: Porosity of sample 30% Container Volume 49.5 cm^3 Cylindrical sample: Diameter 2.5 cm Length 5 cm A vacuum of-10 psig was applied on the container and the volume of total air was sucked into a graduated tube, from which the volume at the condition of vacuum was measured to be 97.77 cm^3. The whole experiment is done under isothermal conditions. Assume that the porosity of the sample was assessed by reliable well logging tools. Calculate the pore volume in the sample, based on the above experiment. What assumption did you make for the calculation? What would be the reason for the difference from the log measurements? Assuming that the difference in measurements is due to the presence of connate water in the sample, calculate the connate water saturation (volume of water per pore volume of rock). Consider the following resistivity data: The location from which the previous sample was retrieved is marked as A. From the resistivity information, the saturation equation: S_w = n squareroot R_0/R_t and the previous experiment, calculate the water saturation at B.

Explanation / Answer

a) pore volume =   [(3.14 * 1.252 * 5)/(49.5)] * 97.77

                         = 48.45 cm3

b) Sw = (236.5/232.11)1/4

            = 1.0047

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