The irregularly shaped area of positive charge in the figure below has an initia
ID: 1524248 • Letter: T
Question
The irregularly shaped area of positive charge in the figure below has an initial surface charge density eta_¡. Then the area is shrunken in such a way that it maintains its shape but each dimension (x and y) of the area is reduced by a factor of 3.163. What is the value of the ratio eta_f/eta_i, where eta_f is the final surface charge density? An electron is located very far away from this area of charge. What is the value of the ratio F_f/F_i, where F_f is the electric force on the electron after the area is reduced and F_i is the initial force on the electron before the area was reduced?Explanation / Answer
(A) surface charge density = charge / area
charge is constant but area is reduced hence charge denisty will increase.
so nf / ni = Ai/ Af = (3.163^2)
nf / ni = 10
(B) as electron is very far away hence this area charge will behave as point charge.
hence force will also be same.
Ff / Fi = 1
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.