incorrect X i Question 8 of 24 ncorrect ncorrect ncorrect Map A Sapling Learning

Question

incorrect X i Question 8 of 24 ncorrect ncorrect ncorrect Map A Sapling Learning There are two identical, positively charged conducting spheres fixed in space. The spheres are 33.2 cm apart (center to center) and repel each other with an electrostatic force of FE0.0750 N. Then, a thin conducting wire connects the spheres, redistributing the charge on each sphere. When the wire is removed the spheres still repel but with a force of F2E0.115 N. Using this information, find the initial charge on each sphere, q1 and q2 if initially qh q2. The Coulomb Force constant is k 1/(4meo) 8.99 x 109 N. m2/c2 Number 9.19 x 10 13 C Number 92 1.41 x 10-12 C There is additional feedback available! View this feedback by clicking on the bottom divider bar, Click on the divider Incorrect bar again to hide the additional feedback. Close Previous Give Up & View Solution Try Again Next Ext Explanation

Explanation / Answer

in the second case the charges have been equalized so we may find the charge on each

F = Kc q^2/r^2

0.115 = 8.98E9 q^2 / 0.33^2

q = 1.188E-6 C
now the total positive charge is double that because there are two objects
total = 2.36E-6 C
so in the first condition
q1+q2 = 2.36E-6
q2 = 2.36E-6 - q1
and
0.0750 = 8.98E9 (q1) (2.36E-6 - q1) / 0.33^2
1.179E-12 = 2.736E-6 q1 - q1^2
q1^2 - 2.736E-6 q1 + 1.179E-12 = 0
q1 = 2.20E-6 or 5.36E-7

then q1 is greater than q2
but we are given that q1<q2 so we must select the second value
so
q1 = 5.36E-7 C
q2 = 2.736E-6 - 5.36E-7 = 2.20E-6 C

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