Steel pellets with a mass of 1.0 g and a temperature of 85° C are added to 185 g

Question

Steel pellets with a mass of 1.0 g and a temperature of 85° C are added to 185 g of water at 18° C.

(a) How many pellets must be added to increase the equilibrium temperature of the system to 24° C? Assume no heat is exchanged with the surroundings.

(b) If copper pellets are used instead, does the required number of pellets increase, decrease, or stay the same?

(c) Find the number of copper pellets that are required.

Steel pellets with a mass of 1.0 g and a temperature of 85°Care added to 185 g of water at 18° C. (a) How many pellets must be added to increase the equilibrium temperature of the system to 24° C? Assume no heat is exchanged with the surroundings. 338.3894 Your response differs from the correct answer by more than 10%. Double check your calculations (b) If copper pellets are used instead, does the required number of pellets increase, decrease, or stay the same? increases Explain. Score: 1 out of 1 Comment: (c) Find the number of copper pellets that are required.

Explanation / Answer

using the principle of caloriemetry

Heat gained by water = heat lost by the pellets

m_water*S_water*dT_water = (n*m_pellet*S_pellet*dT_pellet)

S_water and S_pellet is the specific heat capacity of water and steel respectievly

185*4186*(24-18) = (n*1*452*(85-24))

no.of pellets required are n = 168

if copper pellets are used

then

Heat gained by water = heat lost by the pellets

m_water*S_water*dT_water = (n*m_pellet*S_pellet*dT_pellet)

185*4186*(24-18) = (n*1*385*(85-24))

no.of pellets required are n = 197

So the answer is increases

Explanation is since the copper has lowest specific heat capacity than steel,so more number of copper pellets are required to reach the given temperature than steel

C) answer is n = 197 as solved above

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