1. For PCR, you want to prepare dilutions of forward and reverse oligos. If you

Question

1.      For PCR, you want to prepare dilutions of forward and reverse oligos. If you were to prepare each dilution in a new tube such that final concentration of each oligo is 10uM, how much of the each 100uM stock and how much water would you need have in a final volume of 100ul solution to get 10uM primer dilution?

2.If you were to prepare a solution of both primers mixed in together but each still at 10uM in a final volume of 100ul, how much of each stock primer and how much water would you add?

Note: please label and show all steps!

Explanation / Answer

Yoi can use the simple dilution formulae to calculate how much neds to be added:

C1V1 = C2V2

1) For this,

100uM x X = 10uM x 100uL

so, X= 10uL, meaning 10uL of 100uM is needed in 100uL to make 10uM solution so the resy 90uL would be water.

2) since the concentration is not changing,

so forward primer = 10ul

reverse primer = 10ul

and the rest 80uL = water.

Feel free to leave a comment down below for any further query. Good rating would be appretiated if you find my answer helpful. Thank you.

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