9:21 PM AT&T; 47% session.masteringphysics.com Problem 3 MasteringPhysics A squa

Question

9:21 PM AT&T; 47% session.masteringphysics.com Problem 3 MasteringPhysics A square insulating sheet 90.0 cm on a side is held horizontally. The sheet has 5.50 nC of charge spread uniformly over its area. Part A Calculate the magnitude of the electric field at a point 0.100 mm above the center of the sheet. Express your answer with the appropriate units. E Value Units Give Up Submit Part B Estimate the magnitude of the electric field at a point located a distance 200 m above the center of the sheet. E 353x10-5 N/C OE 55 x 10 N/C -4 O E 24x10-3 N/C 22 in 2 N/C

Explanation / Answer

Part A:

Since the distance of point is very small compared to size of sheet, therefore, the sheet can be treated as infinite sheet of charge.

Again, please note that the electric field due to infinite sheet does not depend on distance of point from sheet.

So, the electric field due to infinite sheet = E = Q / 2eo

=> E = (5.50x10^-9) / [2x(0.90)^2*8.85*10^-12) =

E = 348.75 N/C

Part B:

Third option 1.24 x 10^-3 N/C is the correct answer.

Further, the sheet can be treated as point charge for calculating electric field at a point located a distance 200 m above the center of the sheet.

The electric field at a point located a distance 200 m above the center of the sheet.=kq/r^2

E =9*10^9*5.50*10^-9 /200*200=1.72125*10^-3 N/C

The electric field at a point located a distance 200 m above the center of the sheet.= 1.24 x 10^-3 N/C.

Part C:

Last option, 'neither answer would change' is the correct answer.

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