Please help me with this physics question. Thank you very much! The following co

Question

Please help me with this physics question. Thank you very much!

The following constants can be used by name throughout this assignment:

ke = 8.99×109 Nm2/C2

qe = 1.6×10–19 C

mp = 1.67×10–27 kg

me = 9.11×10–31 kg

eps0 = 8.85×10–12 C2/(Nm2)

g = 9.80 m/s2

An ion having a mass of m = 9.45×10–26 kg and charge qe (+1.602×10–19 C) is released a short distance above the surface of the earth. A second identical ion directly below it exerts an electrostatic force on the first ion just great enough to cancel the gravitational force on it. How far below the first ion is the second?
Defined symbols:
   m mass of the ion in kg
   qe charge of the ion in C
   The answer is r the distance that the first ion is below the second, in mm
Hints:
    Be sure to convert your answer to mm.
    Range of answers: 15.5 mm to 18 mm

Explanation / Answer

mass of first ion is m = 9.45 * 10^-26 kg

the gravitational force on this particle is Fg = m*g

Fg = 9.45 * 10^-26 * 9.8 N

the electrostatic force on this ion due to another ion at a distance r below is

Fe = k * q * q / r^2

Fe = 8.99 * 10^9 * 1.6 * 10^-19 * 1.6 * 10^-19 / r^2

when the gravitational force is balanced by the electrostatic force

Fe = Fg

8.99 * 10^9 * 1.6 * 10^-19 * 1.6 * 10^-19 / r^2 = 9.45 * 10^-26 * 9.8

r = 15.76 mm------------------------Answer

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