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A laser beam with a cross-sectional area of 0.001 m^2 and an intensity of 500 W/

ID: 1522704 • Letter: A

Question

A laser beam with a cross-sectional area of 0.001 m^2 and an intensity of 500 W/m^2 perpendicularly strikes a flat black slab with a mass of half a kilogram. If the slab is floating in space, find the acceleration it experiences from photon pressure. A laser beam with a cross-sectional area of 0.001 m^2 and an intensity of 500 W/m^2 perpendicularly strikes a flat black slab with a mass of half a kilogram. If the slab is floating in space, find the acceleration it experiences from photon pressure.

Explanation / Answer

P = I*A
So, P = 500 * .001
= 0.5 W

Now, Acceleration = Power / (Mass * Speed)
So, a = 0.5 / (0.5*3*10^8)

or a = 3.33 * 10^-9 m/s^2

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