A rectangular current carrying 44 turn coil, as shown in the figure, is pivoted

Question

A rectangular current carrying 44 turn coil, as shown in the figure, is pivoted about the z axis. The current in the coil is I = 1.55 A. If the wires in the z = 0 plane make an angle 0 = 35degree with the y axis, what angle does the magnetic moment of the coil make with the unit vector i ? Write an expression for n in terms of the unit vectors I and j, where n is a unit vector in the direction of the magnetic moment. What is the magnetic moment of the coil? Find the torque on the coil when there is a uniform magnetic field B = 1.1 T j in the region occupied by the coil.

Explanation / Answer

a) u = IA

angle made by u with y axis = 90 + 35

then angle madewith x axsi = 90 + 35 - 90 = 35 deg

b) ncap = cos35i - sin35j = 0.819i - 0.574j

c) magntic moment = NIA = 44 x 1.55 x 0.05 x 0.08 = 0.273

moment vector = 0.223i - 0.157j

d) toruqe = u x B

   = 0.223i - 0.157j) x ( 1.1j )

     = 0.245k N.m

e) U = - mu. B = - (0.223i - 0.157j).( 1.1j ) = 0.173 J

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