(Updated question for the part that\'s not shown!!!) A cat (Mcat = 5.6 kg) jumps

Question

(Updated question for the part that's not shown!!!)
A cat (Mcat = 5.6 kg) jumps onto the sled (Msled = 32 kg) that is sliding along an ice over take.
A) suppose that the car moving with an initial speed of 12.2 m/s jumps onto a sled moving at a speed of 3.63 m/s direction. What would the final speed of the sled/car after the cat lands on the sled?
B) if the sled slides a distance of 75 cm while it is accelerating, calculate the force acting on the sled.
C) using the force from part (B), calculate the time it took for the sled to accelerate. m-5.6 kg) jumwith an aofthe Suppose that the cat mane final kg) jumps ie Bat hes jumps onto a sledMaf 32 kg) that is sliding along an ice.ovr lake (B) If the sled slides a distance at wouig with an initial speed of 12.2 m/s jumps onto a sled moving at a speed of 3 Wou ld the final speed of the sled/cat after the cat lands on the sled? C) Using the force from part. slides a distance of 75 cm e distance of 75 cm while it is accelerating, calculate the force scting on the sed part (B), calculate the time it took for the sled to accelerate.

Explanation / Answer

a) Applying momentum conservation for sled-cat system,

initial momentum of system = final momentum of system

5.6 * 12.2 + 32 * 3.63 = (5.6 + 32) v

v = 4.91 m/s

b) using vf^2 - vi^2 = 2 a d

4.91^2 - 3.63^2 = 2(a) (0.75)

a = 7.26 m/s^2

c) using,

v - u = at

4.91 - 3.63 = 7.26t

t = 0.176 sec

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