The magnetic field of a sinusoidal electromagnetic wave obeys the equation B(x,

Question

The magnetic field of a sinusoidal electromagnetic wave obeys the equation B(x, t) = 3.5 nT sin [(5.89 times 10^15)t - (1.91 times 10^7 rad/m)x] What is the amplitude of electric field in this wave? What is the wavelength of the wave What is the period of this wave What is the intensity of this wave If this wave is absorbed by a perfectly absorbing surface, what is the radiation pressure If the wave enters glass (index of refraction n=1.5) what will be the wavelength of this wave in glass? Light of wavelength 700 nm is incident on the face of a fused quartz prism (n = 1.458 at 700 nm) at an incidence angle of theta_1 = 75 degree. The apex angle of the prism is alpha = 60 degree. Calculate the angle theta_2 of refraction at the first surface theta_3 of incidence at the second surface theta_4 of refraction at the second surface delta - between the incident and emerging rays

Explanation / Answer

@1 = 75 deg

Applying snell's law,

ni sini = nr sinr

1 * sin75 = 1.458 * sin@2

@2 = 41.5 deg

b) for using traingle geometry,

(90 - @2) + alpha + (90 - @3) = 180   ( sum of angles of triangle)

90 - @3 = 71.49

@3 = 18.5 deg

c) using snell's law again,

1.458 * sin18.5 = 1 * sin@4

@4 = 27.57 deg

d) angle of incident ray with first refracted ray = @1 - @2 = 75 - 41.5 = 33.5 deg

now angle of emerging ray from first refracted ray = @4 - @3 = 9.07 deg

angle between them = 33.5 + 9.07 = 42.57 deg

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