In the figure a block slides along a path that is without friction until the blo

Question

In the figure a block slides along a path that is without friction until the block reaches the section of length L = 0.74 m, which begins at height h = 1.2 m, on a ramp of angle ? = 30 ?. In that section the coefficient of kinetic friction is 0.460 . The block passes through point A with a speed of 8.8 m/s. If the block can reach point B (where the friction ends), what is its speed there, and if it cannot, what is its greatest height above A?

In the figure a block slides along a path that is without friction until the block reaches the section of length L = 0.74 m, which begins at height h = 1.2 m on a ramp of angle = 30 In that section the coefficient of kinetic friction is 0.460. The block passes through point A with a speed of 8.8 m/s. If the block can reach point B (where the friction ends), what is its speed there, and if it cannot, what is its greatest height above A? uni Unit m/5 Numbe

Explanation / Answer

Here,

L = 0.74 m

h = 1.2 m

theta = 30 degree

uk = 0.460

let the final speed of block is v

Using conservation of energy

0.5 * m * (v^2 - 8.8^2) = - m * g * (0.74 * sin(30) + 1.2) - us * m * g * L * cos(theta)

0.5 * (v^2 - 8.8^2) = -9.8 * (0.74 * sin(30) + 1.2) - 0.406 * 9.8 * 0.74 * cos(30)

solving for v

v = 6.44 m/s

the speed of the block at point B is 6.44 m/s

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.