Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

PLEASE PROVIDE EXPLAINATION TO ALL QUESTIONS, thank you! 1.) At point P in the f

ID: 1521407 • Letter: P

Question

PLEASE PROVIDE EXPLAINATION TO ALL QUESTIONS, thank you!

1.) At point P in the figure shown below, the electric field is zero.

(A) What are the signs of q1 and q2?

a) The signs of the charges will entirely depend on the magnitudes of them.

b) all of these    

c) The charges q1 and q2 must have opposite signs.

d) The charges q1 and q2 must have equal signs.


(B) Describe their magnitudes.

a) Charge q1 must have a larger magnitude to counter the fact that it is closer to P.

b) Charge q2 must have a lower magnitude to counter the fact that it is farther away from P.    

c) Charge q2 must have a larger magnitude to counter the fact that it is farther away from P.

d) Charge q1 must have a larger magnitude to counter the fact that it is farther away from P.

2.) In the figure shown below, if

q1 = 108 C

and

q2 = 2 108 C,

answer the following questions.

Explanation / Answer

1)

A)neutral point lies out side of the charges so charges are opposite signs then option c correct

B)in this case q1/x2=q2/(r+x)2

so q2 has larger magnitude than q1 and it is farther away from point P so option c is correct

2 a)along the X axis at point 0 total electric field E=k(q1/r12+q2/r22)

here q1=10-8 c,q2=2*10-8,r1=5*10-2m,r2=8*10-2m,k=9*109

Ex=9*109(10-8/25*10-4 +2*10-8/64*10-4)=64125N/c x

along

the Y axis at point 4 total electric field E=k(q1/r12+q2/r22)

here q1=10-8 c,q2=2*10-8,r12=1625*10-4m,r22=1664*10-4m,k=9*109

Ex=9*109(10-8/1625*10-4 +2*10-8/1664*10-4)=1635N/c y

b)force f =kq1q2/r2

here r=3*10-2m

F=9*109(10-8*2*10-8)/9*10-4=2*10-3 Nalong x axis

along y axis force is zero

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote