Six marshmallows are placed in a row touching one another on a paper plate in a

Question

Six marshmallows are placed in a row touching one another on a paper plate in a microwave that has a frequency of 2450 MHz. They are microwaved until marshmallows start to melt and inflate. The average distance from the marshmallow hotspots is 3 cm. Based on this information answer the following:

1) Based on the measurment of the hot spots what is the wavelength of the microwave?

2) Calculate the wave speed of microwaves from the labeled frequency and your measured distance.

3) Compute the percent error between the calculated speed with the speed of light (3.0 x 108 m/s). Is this speed close to the speed of light (c = 3.00 x 108 m/s)? Explain why or why not.

Explanation / Answer

Given that

Frequency (f) =2450Hz

The average distance from the emarshmallow hotspots is (davg) =3cm =0.03m

We know that wavelength of the microwave is given by

v =f*lamda

Then lamda =v/f =c/f =3*108m/s/2450Hz =1.224*105m

Wave speed (v) =f*lamda =(2450Hz)(1.224*105m) =2998.8*105m/s =2.9988*108m/s

Now the percentage error is given by

[3.0 x 108 m/s -2.9988*108m/s]*100/3.0 x 108 m/s=0.04

It is very close to the speed of the light

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.