Gravitational Force of Three Identical Masses Three identical very dense masses
ID: 1520047 • Letter: G
Question
Gravitational Force of Three Identical Masses Three identical very dense masses of 3000 kg each are placed on the x-axis. One mass is at x_1 = -120 cm, one is at the origin, and one is at x_2 = 300 cm. What is the magnitude of the net gravitational force F_grav on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67 times 10^-14 Nm^-2/kg^2 Express your answer in newtons to three significant figures. What is the direction of the two gravitational force on the mass at the origin due to the other two masses?Explanation / Answer
let m1 =m2 = m3 = 3000 kg
Force due to mass at x1 = -120 cm = -1.2 m
then F1 = G*m1*m2/x1^2 = (6.67*10^-11*3000^2)/(1.2^2)= 4.16*10^-4 N
similarly F2 = G*m2*m3/x2^2 = (6.67*10^-11*3000^2)/(3^2) = 0.667*10^-4 N
Fnet = F2-F1 = (0.667-4.16)*10^-4 = -3.49*10^-4
So answer for Part A is
F = 3.49*10^-4 N
Part B)
direction is along -X-axis
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