Please report the detailed steps for each of following calculations clearly and-

Question

Please report the detailed steps for each of following calculations clearly and-legibby nderstanding these calculati onl ial for the lab but also for chapter 2 in-your lecture I. Preparation of 0.2 M sodium ocetate and 0.2 M acetic acid stock solutions a. Using density and percentage purity to calculate the molarity of glacial acetic ai b. How will you prepare 400 ml ot o.200 M acetic acid from a bottle a concentrated glactal acetic acicd c. Preparation Preparation of acetate buffer solutions a. How will you prepare a 0.200 M acetate buffer pH 4.50 from the o.200 M of 0.200 M sodium acetate acetic acid and 0.200 M sodium acetate. b. What is the pH of the 0.200 M acetate buffer made by mixing 69.0 ml of 0.200 M sodium acetate solution and 50.0 ml of the 0.200 M acetic acid solution

Explanation / Answer

1.preparation of 0.2 M sodium acetate solution and 0.2 M acetic acid stock solution

Molarity =WEIGHT(IN GRAMS)/MOLECULAR WEIGHT(IN Daltons)/volume in litre[note this formula is for solute only]

A,    0.2 M sodium acetate solution

Molar mass: 82.0343 daltons

Therefore

0.2M=wt(g)/82.0342 dalton/1 litre

Wt(g)=0.282.032=16.4 grams

Important step   weight 16.4 grams sodium acetate and dissolve in approx 200ml double distilled water and after dissole step maintain the water upto 1litre final volume,then the resulting solution will be 0.2M sodium acetate stock solution

b .0.2 M acetic acid stock solution

for acids molarity =For acids molarity = {(percentage purity specific gravity or density)/mol weight } 10

Molar mass: 60.05 g/mol

Density: 1.05 g/cm³

Molarity=0.2M

PERCENTAGE PURITY=99.7 % (MOSTLY)

DESIRED VOLUME =1 LITRE

PUT VAUES IN ABOVE FORMULA ,WE GET

M=17.416

HENCE stock solution of Acetic Acid is calculated to be 17.416 M based on a density of 1.049 g/mL, a formula weight of 60.05 g/mol, and a concentration of 99.7% w/w.

To make a 0.2 M solution, slowly add 11.483 mL of your stock solution to 250 mL deionized water.
Adjust the final volume of solution to 1000 mL with deionized water.

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