Under electrostatic conditions, the electric field just outside the surface of a
ID: 1519873 • Letter: U
Question
Under electrostatic conditions, the electric field just outside the surface of any charged conductor is equal to the electric field just inside the surface of the conductor. can have nonzero components perpendicular to and parallel to the surface of the conductor, if it is not symmetric. is always zero. is always perpendicular to the surface of the conductor. is always parallel to the surface of the conductor. Two point charges of +2.0 mu C and -6.0 mu C are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0-mu C be placed on the +x-axis so that the potential at the origin is equal to zero? x = 3.0 cm x = 5.0cm x = 1.0cm x = 2.0 cm x = 4.0cm In a region of space, there is a charge q = 3.60 mu C and an additional uniform electric field E = (9.5 Times 10^5 N/C) i. Calculate the total electric flux, in SI units, through a Gaussian sphere of radius R = 10.0 cm centered on the charge. zero 4.22 Times 10^5 4.69 Times 10^5 6.28 Times 10^4 4.07 Times 10^5 A conducting sphere is positivly charged with the charge distributed uniformly over its surface. Which statements about the potential due to this sphere are true? The zero of potential is at infinity. The potential is lowest, but not zero, at the center of the sphere. The potential diverges to infinity at the center. Tine potential at the center of the sphere is the same as the potential at the surface. The potential at the center is higher (but not infinity) than the potential at the surface. The potential at the center of the sphere is zero. A nonuniform electric field is directed along the x-axis at all points in space. The axis of a cylindrical surface, 0.80 m long with radius of 0.10 m, is aligned parallel to the x-axis, as shown in the figure. The electric fields E_1 and E_2, at the ends of the cylindrical surface, have magnitudes of 9000 N/C and 5000 N/C respectively. The charge enclosed by the cylindrical surface is 3.1 nC. -1.1 nC. Zero -8.9nC. 3.9 nC.Explanation / Answer
1) Answer is (D) option. Electric field just outside surface of charged conductor is normal to conductor at that point.
It can be explained on the basis of the fact that, Electric field inside conductor under static conditon is zero. As a result potential difference between any two points with in conductor is zero. So whole of conductor is euipotential body.
Equipotential surface and Electric field lines always cut at 90 degrees to each other. Conductor being equipotential body, Electric field lines starting or terminating at condutor must be normal to surface. Hence electric field just outside condutor is perpendicular or normal to surface.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.