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Question 16 of 17 ncorrect Map sapling learning In each of the four scenarios to

ID: 1519624 • Letter: Q

Question

Question 16 of 17 ncorrect Map sapling learning In each of the four scenarios to the right, a large bat lets out a short burst of ultrasonic sound, which the smaller bat hears a moment later. If the large bat flies at 14.00 m/s and the small bat flies at 3.530 m/s, rank the frequency that the smaller bat detects in the four scenarios, from highest to lowest. Assume that the speed of sound is 343.0 m/s. highest frequency lowest frequency In scenario C, some of the large bat's signal reflects off of the small C bat and returns to the large bat, warning it of the smaller bats presence. If the initial signal has a frequency of 24.30 kHz, what return frequency will the large bat detect? Calculate the final frequency to four significant figures. There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint. kHz Close A Previous Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

f = Fo•(V + Vr)/(V + Vs) Doppler
Vr +ve if rcvr moving toward srce; Vs -ve if srce moving toward rcvr

A: f = Fo*(343.0 - 3.53) / (343.0 - 14) = 1.03182 * Fo
B: f = Fo*(343.0 - 3.53) / (343.0 + 14) = 0.9509 * Fo
C: f = Fo*(343.0 + 3.53) / (343.0 - 14) = 1.0533* Fo
D: f = Fo*(343.0 + 3.53) / (343.0 + 14) = 0.9707 * Fo

I get C-A-D-B.

Then
f = 24.30kHz * (343.0 + 3.53)*(343.0 + 14) / [(343.0 - 3.53)*(343.0 - 14)]
f = 24.30kHz * 123,711.21/ 111,685.63 = 26.9165 kHz

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