PART-II: Multiple Choice A positive charge of 20-nC travels horizontally along t

Question

PART-II: Multiple Choice A positive charge of 20-nC travels horizontally along the negative x-axis at velocity of 10 m/s. The charges encounters a magnetic field of magnitude of 5 times 10^-5 T pointing in the positive y-direction. Calculate the magnitude of the magnetic force on this charge. 1 times 10^-11 J 1 times 10^-11 N 3 times 10^-13 W 1 times 10^-15 N None A conductor carries a current of 5A for 4min. What is the number of electrons that passes through the cross sectional area of the conductor? [Note, first determine the number of charges in Coulomb] 7.50 times 10^23 9.50 times 10^21 7.50 times 10^21 8.50 times 10^21 None A parallel plate capacitor is filled with a dielectric constant 3.4. Each plate has an area of 4.0 m^2 is separated by 4.00 mm. Calculate the capacitance of the capacitor. 8.85 pF 8.85 mF 30.0 pF 3.0 muF None

Explanation / Answer

1)

charge, q=20*10^-9 C

velocity, v=10 m/sec

magnetic field, B=5*10^-5 T

magnetic force, F=q*V*B*sin(theta)

F=20*10^-9*10*5*10^-5*sin(90)

F=1*10^-11 N

option (B) is correct

2)

current, i=5 A,

time, t=4min

i=n*q/t

5=n*1.6*10^-19/(4*60)

===> n=7.5*10^21

no of electrons, n=7.5*10^21

option (C) is correct,

3)

dielectric constant, k=3.4

area of capacitor plate, A=4 m^2

separation between the plate, d=4*10^-3 m

C=K*eo*A/d

C=3.4*8.85*10^-12*4/(4*10^-3)

C=3.01*10^-8 F

C=30.1 nF

option (c) is correct

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