The free-fall acceleration on Mars is 3.7 m/s^2. What length of pendulum has a p

Question

The free-fall acceleration on Mars is 3.7 m/s^2. What length of pendulum has a period of 1.2 s on Earth? Use the relation between the length of a pendulum and its period, cm What length of pendulum would have a 1.2-s period on Mars? Use the relation between the length of a pendulum and its period, cm An object is suspended from a spring with force constant 10 N/m. Find the mass suspended from this spring that would result in a period of 1.2 s on Earth. kg Find the mass suspended from this spring that would result in a period of 1.2 s on Mars. kg

Explanation / Answer

a) T = 2pi*sqrt(l/g)

1.2 = 2pi*sqrt(L/9.8)

L = 0.357 m

b) 1.2 = 2pi*sqrt(L/3.7)

L =0.135 m

c) T = 2pi*sqrt(K/m)

1.2 = 2pi*sqrt(10/m)

m = 274.15 Kg

d) T = 2pi*sqrt(K/m)

1.2 = 2pi*sqrt(10/m)

m = 274.15 Kg

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