calculate the minimum thickness of a light soap film, n=1.2, that will result in

Question

calculate the minimum thickness of a light soap film, n=1.2, that will result in constructive interference in the reflected light, if the film is illuminated with wavelength 602nm in free space and the soap is floating on water calculate the minimum thickness of a light soap film, n=1.2, that will result in constructive interference in the reflected light, if the film is illuminated with wavelength 602nm in free space and the soap is floating on water calculate the minimum thickness of a light soap film, n=1.2, that will result in constructive interference in the reflected light, if the film is illuminated with wavelength 602nm in free space and the soap is floating on water

Explanation / Answer

for reflection to be constructive:
2*n*t = (m-1/2)* lambda
2*1.2*t = (1-1/2)*602
2*1.2*t = 602/2
t = 125.4 nm
Answer: 125.4 nm

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