B) Due to practical constraints, the largest magnetic field that the solenoid ca

Question

B) Due to practical constraints, the largest magnetic field that the solenoid can actually produce is 3.50 × 10-3 T. You decide to compensate by using multiple loops of the conductive material in series. How many conductive loops should be in the chest band?

5/5/2016 02:00 AM 0/5 Gra -Print Ed Calculator -d Periodic Table Periodic Table Question 1 of 1 Map sapling leaning You are designing an apparatus to monitor the breathing of a patient. The apparatus consists of a stretchable loop of conductive material wrapped in a small band around the patient's chest. A constant uniform external magnetic field is produced by a nearby solenoid. As the patient inhales, his chest expands, stretching the chest band. The resulting increase in the area of the loop causes an emf to be induced in the loop. By measuring the induced emf, you can estimate the patient's breathing rate. You want your apparatus to be able to detect a change in area as small as 5.50 cm2 occuring over a time period of 1.50 s. If the minimum emf that can be reliably detected is 3.00 10-4 V, what is the magnitude of the minimum external magnetic field that would be needed from the solenoid? Number Due to practical constraints, the largest magnetic field that the solenoid can actually produce is 3.50 x 10-3 T You decide to compensate by using multiple loops of the conductive material in series. How many conductive loops should be in the chest band? Number Previous Q Check Answer Next Exit

Explanation / Answer

Here,

change in area, A = 5.5 cm^2 = 5.5 *10^-4 m^2

time , t = 1.50 s

emf = 3 *10^-4 V

let the magnitude of minimum external field is B

emf = B * change in area/time

3 *10^-4 = B * 5.5 *10^-4/(1.50)

B = 0.818 T

the magnetic field needed is 0.818 T

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let the number of turns is N

N * 3.5 *10^-3 = 0.818

N = 233.7 = 234

the number of conductive loops is 234

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