You connect 100-Ohm (R_1) and 20-Ohm (r_2) resistors in parallel to a 12-V DC vo

Question

You connect 100-Ohm (R_1) and 20-Ohm (r_2) resistors in parallel to a 12-V DC voltage source as shown in Figure. Answer the following questions. What is the potential difference across the 100-Ohm resistor (R_1) 1O V. 6.0 V, 12 V. 5.0 V What is the potential difference across the 20-Ohm resistor (R_3)? lO V. 6.0 V. 12 V. 5.0 V What is the current I_1 that goes through the 100-Ohm resistor (R_1)? 8.3 A, 1.7 A. 0.12 A, 0.60 A What is the current I_2 that goes through the 20-0 resistor (R-2)? 8.3 A. 1.7 A. 0.12 A. 0.60 A Find the total (equivalent) resistance R of ircuit? 120 Ohm. 100 Ohm. 33 Ohm. 17 Ohm

Explanation / Answer

Both resistor are in parallel so

A)

potential difference across 100 ohm = 12 volt

B)

potential difference across 20 ohm = 12 volt

E)

equivalent resistance = 100*20/(100 + 20) = 16.67 ohm

C)

current through battery = 12/16.67 = 0.72 amp

so current through 100 ohm = i1 = 20*0.72/(100 + 20) = 0.12 amp

D)

current through 20 ohm = i2 = 100*0.72/(100 + 20) = 0.6 amp

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