HELP! I do not understand this types of calc problems. My final is tonight and I
ID: 1516799 • Letter: H
Question
HELP! I do not understand this types of calc problems. My final is tonight and I'm stressing
A 55 gallon drum is 22.5" in diameter, and 33.5" tall. If the drum is upright and half full with a petroleum based product that has a density of 850 kg/m3, how much work is required to pump the liquid out of the top of the drum? Use 2.54 cm = 1 inch. F = m astir g g= 9.8 m/s^2 m = density astir volume A 3 ft. diameter punch bowl is the shape of a hemisphere, and is filled to the top with a non-alcoholic beverage. How much work is required by all the party-goers to remove all the punch from the bowl? The density of punch is 65.5 lb/ft3, g = 32.2 ft/s^2. A triangular trough is 3 m wide at the top, 8 m long, 4 m tall, and has spout 2 m above the top of the trough. Find the work to pump out all the water in the trough through the spout. g = 9.8 m/s2, mass = dens middot vol, F = mg, the density of water is 1000 kg/m^3. Find the total hydrostatic force on the triangular face of the trough before any water is removed. Pressure = dens middot g middot depth, F = pressure middot area What's the total hydrostatic force on a 20 in diameter circular window on a submarine when the top of the window is 50 ft. below the water surface? Water: 62.5 lb/ft^3 g = 32.2 ft/s^2 A 200 lb cable that's 100 ft long hangs vertically from the roof of a 120 ft. tall building. How much work is required to pull the entire rope to the roof?Explanation / Answer
1) Work required = (rho)gh*V [ the potential energy of the liquid assuming COM of the liquid to be at half the hieght of the symmetric vessel]
where h = 33.5/2 inch
W = 850*9.8*33.5*pi*11.25^2*33.5*0.0254^4/2 = 773.168 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.