The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward

Question

The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward the 2.0 resistor at a steady speed of 0.50 m/s. The magnetic field strength is0.25 T .
(Figure 1)

Part A

How big is the pushing force?

Express your answer with the appropriate units.

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Part B

How much power does the pushing force supply to the wire?

Express your answer with the appropriate units.

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Part C

What is the magnitude of the induced current?

Express your answer with the appropriate units.

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Part D

What is the direction of the induced current?

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Part E

How much power is dissipated in the resistor?

Express your answer with the appropriate units.

Explanation / Answer

emf induced= Blv=0.25*10*0.5/100=0.0125V

power=E^2/R=(0.0125)^2/2=7.8125*10^-5W

force=power/velocity=7.8125*10-5/0.5=15.625*10^-5N

power=7.8125*10^-5W

induced current=E/R=0.0125/2=0.00625A

by right hand rule direction of induced current=anticlockwise

power dissipiated in resistor = i^2R=0.00625^2*2=7.8125*10^-5W

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