O 5/2/2016 11:00 PM A 72.9/100 O 5/2/2016 09:48 PM Gradebook Print Calculator Pe

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O 5/2/2016 11:00 PM A 72.9/100 O 5/2/2016 09:48 PM Gradebook Print Calculator Periodic Table Question 13 of 16 Map Presented by Physics openstax sapling learning How much total heat transfer is necessary to lower the temperature of 0.335 kg of steam from 129.5 °C to 19.5 °C, including the energy for phase changes? Number How much time is required for each stage of this process, assuming a constant 835.0 Wrate of heat exchange? Give the times in the order that the stages occur Number Number Number Number Number O Previous ® Give Up & View Solution Check Answer Next HExit Hint

Explanation / Answer

Q= m Csteam deltaT + m Lv + m Cwater deltaT + m Lf + m Cice deltaT

Csteam = 1.996 kJ / kg K

Cwater = 4.186 kJ/kg K

Cice = 2.108 kJ / kg K

Lv = 2257 kJ/kg

Lf = 334 kJ / kg

Q = (0.335 * 1.996 * (129.5 -100)) + (0.335 * 2257) + (0.335 * 4.186 * (100 -0))

+ (0.335 x 334) + (0.335 x 2.108 x (19.5))

Q = 19.73 + 756.1 + 140.23 + 111.89 + 13.77

= 1041.72 kJ Or 1041720 J

Power = Q/ t

time to come to boiling pooint= Q/P = 19730 / 835 = 23.63 sec

t2 = 756100 / 835 = 905.5 sec

t3 = 140230/835 = 167.94 sec

t4 = 111890 / 835 = 134 sec

t5 = 13770/835 = 16.5 sec

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