The radius of curvature of a mirror is 46 cm. A diamond ring is placed in front

Question

The radius of curvature of a mirror is 46 cm. A diamond ring is placed in front of this mirror. The image is three times the size of the ring. (iii) What are the possible values for the magnification of the image of the ring? (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.) Calculation: Find the possible object distances of the ring. (Enter your answers from smallest to largest starting with the first answer blank. Enter NONE in any remaining answer blanks.)

Explanation / Answer

here,

radius of curvature of mirror, r = 46 cm
focal length of mirror, f = 46/2 = 23 cm

magnification of image, m = 3

also,
m = -di/do ( di is image distance, do is object distance)

di = -3do

Fromt Thin lens equation,
1/do = 1/f - 1/di
1/do = 1/23 + 1/(3*do)
do = 15.333 cm

The first object distance, do = 15.33 cm from mirror

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