Please show all work and specify the correct answer at the bottom, and do not pu

Question

Please show all work and specify the correct answer at the bottom, and do not put down an answer that is not one of the choices.

The howler monkey is the loudest land animal and, under some circumstances, can be heard up to a distance of 6.9 km. Assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0 × 10-12 W/m2. A juvenile howler monkey has an acoustic output of 58 W. What is the ratio of the acoustic intensity produced by the juvenile howler to the reference intensity I0, at a distance of 460 m?

Explanation / Answer

Here,

acoustic output , I = 58 uW

I = 58 *10^-6 W/m^2

I0 = 1 *10^-12 W/m^2

for the ratio of acoustic intensity produced

ratio = 10 * log(I/I0)

ratio = 10 * log(58 *10^-6/(1 *10^-12))

ratio = 77.63

the atio of the acoustic intensity produced by the juvenile howler to the reference intensity I0 is 77.63

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.