A capacitor with air between it\'s plates is connected to a battery and allowed

Question

A capacitor with air between it's plates is connected to a battery and allowed to fully charge so that it stores an energy of En J. The capacitor is then disconnected from the battery, and a dielectric with constant K = 5 is inserted between its plates. What is the new stored energy of the capacitor as a multiple of En? 1/5 En 25 En 1/25 En The potential difference remains En. 5 En In the circuit below, the battery voltage is capital deltaV_batt = 56 V. After the capacitors fully charge, what is the charge stored on capacitor C_1?

Explanation / Answer

E = Q^2/2C

now dielectric put in capacitor so new capacitance C' = kC = 5C

E' = Q^2/2C' = Q^2/25C = 1/5 * En

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