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Three resistors having resistances of R 1 = 1.47 , R 2 = 2.63 and R 3 = 4.91 res

ID: 1515526 • Letter: T

Question

Three resistors having resistances of R1 = 1.47 , R2 = 2.63 and R3 = 4.91 respectively, are connected in series to a 28.5 V battery that has negligible internal resistance.

Part A

Find the equivalent resistance of the combination.

Req =   

Part B

Find the current in each resistor.

Answer in the order indicated. Separate your answers using commas.

IR, IR2, IR3

Part C

Find the total current through the battery.

Part D

Find the voltage across each resistor.

Answer in the order indicated. Separate your answers using commas.

VR1, VR2, VR3

Part E

Find the power dissipated in each resistor.

Answer in the order indicated. Separate your answers using commas.

PR1, PR2, PR3

I= ?

Explanation / Answer

A. Req for series resistance = R1 + R2 + R3 = 9.01 ohm
B. Current = I = V/R = 3.16 A
C. Total Current = 3.16 A { current is same for resistors in series}
D. Voltage across R1 = 4.64 V
Voltage across R2 = 8.31 V
Voltage across R3 = 15.531 V
E. Power dissipated = VI
FOr R1 = 14.66 W
For R2 = 26.25 W
For R3 = 49.077 W

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