Three resistors having resistances of R 1 = 1.47 , R 2 = 2.63 and R 3 = 4.91 res
ID: 1515526 • Letter: T
Question
Three resistors having resistances of R1 = 1.47 , R2 = 2.63 and R3 = 4.91 respectively, are connected in series to a 28.5 V battery that has negligible internal resistance.
Part A
Find the equivalent resistance of the combination.
Req =
Part B
Find the current in each resistor.
Answer in the order indicated. Separate your answers using commas.
IR, IR2, IR3
Part C
Find the total current through the battery.
Part D
Find the voltage across each resistor.
Answer in the order indicated. Separate your answers using commas.
VR1, VR2, VR3
Part E
Find the power dissipated in each resistor.
Answer in the order indicated. Separate your answers using commas.
PR1, PR2, PR3
I= ?Explanation / Answer
A. Req for series resistance = R1 + R2 + R3 = 9.01 ohm
B. Current = I = V/R = 3.16 A
C. Total Current = 3.16 A { current is same for resistors in series}
D. Voltage across R1 = 4.64 V
Voltage across R2 = 8.31 V
Voltage across R3 = 15.531 V
E. Power dissipated = VI
FOr R1 = 14.66 W
For R2 = 26.25 W
For R3 = 49.077 W
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.